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153845130073139 is a prime number
BaseRepresentation
bin100010111110101111011100…
…010101000001010000110011
3202011201110011122002001201122
4202332233130111001100303
5130131044311244320024
61303111251014052455
744255641512124661
oct4276573425012063
9664643148061648
10153845130073139
114502439821263a
121530827294a12b
1367ac6c219946b
1429dc2032c5c31
1512bbce8ee8d5e
hex8bebdc541433

153845130073139 has 2 divisors, whose sum is σ = 153845130073140. Its totient is φ = 153845130073138.

The previous prime is 153845130073043. The next prime is 153845130073181. The reversal of 153845130073139 is 931370031548351.

153845130073139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 153845130073139 - 220 = 153845129024563 is a prime.

It is not a weakly prime, because it can be changed into another prime (153845130073339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76922565036569 + 76922565036570.

It is an arithmetic number, because the mean of its divisors is an integer number (76922565036570).

Almost surely, 2153845130073139 is an apocalyptic number.

153845130073139 is a deficient number, since it is larger than the sum of its proper divisors (1).

153845130073139 is an equidigital number, since it uses as much as digits as its factorization.

153845130073139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 53.

The spelling of 153845130073139 in words is "one hundred fifty-three trillion, eight hundred forty-five billion, one hundred thirty million, seventy-three thousand, one hundred thirty-nine".