Base | Representation |
---|---|
bin | 100010111110101111011100… |
… | …010101000001010000110011 |
3 | 202011201110011122002001201122 |
4 | 202332233130111001100303 |
5 | 130131044311244320024 |
6 | 1303111251014052455 |
7 | 44255641512124661 |
oct | 4276573425012063 |
9 | 664643148061648 |
10 | 153845130073139 |
11 | 4502439821263a |
12 | 1530827294a12b |
13 | 67ac6c219946b |
14 | 29dc2032c5c31 |
15 | 12bbce8ee8d5e |
hex | 8bebdc541433 |
153845130073139 has 2 divisors, whose sum is σ = 153845130073140. Its totient is φ = 153845130073138.
The previous prime is 153845130073043. The next prime is 153845130073181. The reversal of 153845130073139 is 931370031548351.
153845130073139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 153845130073139 - 220 = 153845129024563 is a prime.
It is not a weakly prime, because it can be changed into another prime (153845130073339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76922565036569 + 76922565036570.
It is an arithmetic number, because the mean of its divisors is an integer number (76922565036570).
Almost surely, 2153845130073139 is an apocalyptic number.
153845130073139 is a deficient number, since it is larger than the sum of its proper divisors (1).
153845130073139 is an equidigital number, since it uses as much as digits as its factorization.
153845130073139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 53.
The spelling of 153845130073139 in words is "one hundred fifty-three trillion, eight hundred forty-five billion, one hundred thirty million, seventy-three thousand, one hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •