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153845213537 is a prime number
BaseRepresentation
bin1000111101000111100…
…0111010100101100001
3112201002201220121012202
42033101320322211201
510010033333313122
6154401524502545
714054266511231
oct2172170724541
9481081817182
10153845213537
115a277680a84
122599654aa55
131167a0b7442
147636331cc1
15400647be92
hex23d1e3a961

153845213537 has 2 divisors, whose sum is σ = 153845213538. Its totient is φ = 153845213536.

The previous prime is 153845213477. The next prime is 153845213549. The reversal of 153845213537 is 735312548351.

153845213537 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119353666576 + 34491546961 = 345476^2 + 185719^2 .

It is a cyclic number.

It is not a de Polignac number, because 153845213537 - 210 = 153845212513 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153845213491 and 153845213500.

It is not a weakly prime, because it can be changed into another prime (153845219537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76922606768 + 76922606769.

It is an arithmetic number, because the mean of its divisors is an integer number (76922606769).

Almost surely, 2153845213537 is an apocalyptic number.

It is an amenable number.

153845213537 is a deficient number, since it is larger than the sum of its proper divisors (1).

153845213537 is an equidigital number, since it uses as much as digits as its factorization.

153845213537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512000, while the sum is 47.

The spelling of 153845213537 in words is "one hundred fifty-three billion, eight hundred forty-five million, two hundred thirteen thousand, five hundred thirty-seven".