Base | Representation |
---|---|
bin | 10110011001101101001… |
… | …101110011111111000001 |
3 | 12110011112120022122110211 |
4 | 112121231031303333001 |
5 | 200210223220114223 |
6 | 3135112112554121 |
7 | 216135345306343 |
oct | 26315515637701 |
9 | 5404476278424 |
10 | 1539430629313 |
11 | 543961503845 |
12 | 20a428252941 |
13 | b2224535825 |
14 | 5471a385293 |
15 | 2a09ddb3d0d |
hex | 1666d373fc1 |
1539430629313 has 2 divisors, whose sum is σ = 1539430629314. Its totient is φ = 1539430629312.
The previous prime is 1539430629311. The next prime is 1539430629367. The reversal of 1539430629313 is 3139260349351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1296448672689 + 242981956624 = 1138617^2 + 492932^2 .
It is a cyclic number.
It is not a de Polignac number, because 1539430629313 - 21 = 1539430629311 is a prime.
Together with 1539430629311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1539430629311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 769715314656 + 769715314657.
It is an arithmetic number, because the mean of its divisors is an integer number (769715314657).
Almost surely, 21539430629313 is an apocalyptic number.
It is an amenable number.
1539430629313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1539430629313 is an equidigital number, since it uses as much as digits as its factorization.
1539430629313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1574640, while the sum is 49.
The spelling of 1539430629313 in words is "one trillion, five hundred thirty-nine billion, four hundred thirty million, six hundred twenty-nine thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •