1540133437 has 2 divisors, whose sum is σ = 1540133438. Its totient is φ = 1540133436.

The previous prime is 1540133431. The next prime is 1540133449. The reversal of 1540133437 is 7343310451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1464286756 + 75846681 = 38266^2 + 8709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1540133437 is a prime.

It is a super-2 number, since 2×1540133437² = 4744022007530865938, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1540133399 and 1540133408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1540133431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770066718 + 770066719.

It is an arithmetic number, because the mean of its divisors is an integer number (770066719).

Almost surely, 2^1540133437 is an apocalyptic number.

It is an amenable number.

1540133437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1540133437 is an equidigital number, since it uses as much as digits as its factorization.

1540133437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

The square root of 1540133437 is about 39244.5338486776. The cubic root of 1540133437 is about 1154.8337028119.

Adding to 1540133437 its reverse (7343310451), we get a palindrome (8883443888).

The spelling of 1540133437 in words is "one billion, five hundred forty million, one hundred thirty-three thousand, four hundred thirty-seven".