1540134103 has 2 divisors, whose sum is σ = 1540134104. Its totient is φ = 1540134102.

The previous prime is 1540134067. The next prime is 1540134109. The reversal of 1540134103 is 3014310451.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1540134103 is a prime.

It is a super-3 number, since 3×1540134103³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1540134109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770067051 + 770067052.

It is an arithmetic number, because the mean of its divisors is an integer number (770067052).

Almost surely, 2^1540134103 is an apocalyptic number.

1540134103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1540134103 is an equidigital number, since it uses as much as digits as its factorization.

1540134103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 1540134103 is about 39244.5423339348. The cubic root of 1540134103 is about 1154.8338692735.

Adding to 1540134103 its reverse (3014310451), we get a palindrome (4554444554).

The spelling of 1540134103 in words is "one billion, five hundred forty million, one hundred thirty-four thousand, one hundred three".