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154020193 is a prime number
BaseRepresentation
bin10010010111000…
…10100101100001
3101201211000222121
421023202211201
5303412121233
623141104241
73550102315
oct1113424541
9351730877
10154020193
1179a38718
12436b8081
1325ba8a12
1416653b45
15d7c592d
hex92e2961

154020193 has 2 divisors, whose sum is σ = 154020194. Its totient is φ = 154020192.

The previous prime is 154020157. The next prime is 154020197. The reversal of 154020193 is 391020451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101848464 + 52171729 = 10092^2 + 7223^2 .

It is a cyclic number.

It is not a de Polignac number, because 154020193 - 217 = 153889121 is a prime.

It is not a weakly prime, because it can be changed into another prime (154020197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77010096 + 77010097.

It is an arithmetic number, because the mean of its divisors is an integer number (77010097).

Almost surely, 2154020193 is an apocalyptic number.

It is an amenable number.

154020193 is a deficient number, since it is larger than the sum of its proper divisors (1).

154020193 is an equidigital number, since it uses as much as digits as its factorization.

154020193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 154020193 is about 12410.4872184778. The cubic root of 154020193 is about 536.0342679231.

The spelling of 154020193 in words is "one hundred fifty-four million, twenty thousand, one hundred ninety-three".