Base | Representation |
---|---|
bin | 10110011010011110100… |
… | …010100000100100110111 |
3 | 12110020200020102110120101 |
4 | 112122132202200210313 |
5 | 200213422040412143 |
6 | 3135330153214531 |
7 | 216165014105344 |
oct | 26323642404467 |
9 | 5406606373511 |
10 | 1540258138423 |
11 | 544246623674 |
12 | 20a619401447 |
13 | b2326aca9a4 |
14 | 547982317cb |
15 | 2a0eb871b4d |
hex | 1669e8a0937 |
1540258138423 has 2 divisors, whose sum is σ = 1540258138424. Its totient is φ = 1540258138422.
The previous prime is 1540258138417. The next prime is 1540258138439. The reversal of 1540258138423 is 3248318520451.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1540258138423 is a prime.
It is a super-3 number, since 3×15402581384233 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1540259138423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770129069211 + 770129069212.
It is an arithmetic number, because the mean of its divisors is an integer number (770129069212).
Almost surely, 21540258138423 is an apocalyptic number.
1540258138423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1540258138423 is an equidigital number, since it uses as much as digits as its factorization.
1540258138423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 921600, while the sum is 46.
The spelling of 1540258138423 in words is "one trillion, five hundred forty billion, two hundred fifty-eight million, one hundred thirty-eight thousand, four hundred twenty-three".
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