Base | Representation |
---|---|
bin | 11100101100011011… |
… | …00101010110000001 |
3 | 1110202121022101010201 |
4 | 32112031211112001 |
5 | 223022142420441 |
6 | 11024343325201 |
7 | 1053515502664 |
oct | 162615452601 |
9 | 43677271121 |
10 | 15405045121 |
11 | 6595823454 |
12 | 2b9b150801 |
13 | 15b6735b1b |
14 | a61d3d6db |
15 | 602672c31 |
hex | 396365581 |
15405045121 has 2 divisors, whose sum is σ = 15405045122. Its totient is φ = 15405045120.
The previous prime is 15405045119. The next prime is 15405045143. The reversal of 15405045121 is 12154050451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14470887025 + 934158096 = 120295^2 + 30564^2 .
It is a cyclic number.
It is not a de Polignac number, because 15405045121 - 21 = 15405045119 is a prime.
Together with 15405045119, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 15405045121.
It is not a weakly prime, because it can be changed into another prime (15405045151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7702522560 + 7702522561.
It is an arithmetic number, because the mean of its divisors is an integer number (7702522561).
Almost surely, 215405045121 is an apocalyptic number.
It is an amenable number.
15405045121 is a deficient number, since it is larger than the sum of its proper divisors (1).
15405045121 is an equidigital number, since it uses as much as digits as its factorization.
15405045121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
Adding to 15405045121 its reverse (12154050451), we get a palindrome (27559095572).
The spelling of 15405045121 in words is "fifteen billion, four hundred five million, forty-five thousand, one hundred twenty-one".
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