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1540544540441 is a prime number
BaseRepresentation
bin10110011010101111100…
…111000010111100011001
312110021102012100012021112
4112122233213002330121
5200220013400243231
63135414423550105
7216205062351554
oct26325747027431
95407365305245
101540544540441
1154438325a755
1220a6992bb335
13b237124733a
14547c42a569b
152a116a9692b
hex166af9c2f19

1540544540441 has 2 divisors, whose sum is σ = 1540544540442. Its totient is φ = 1540544540440.

The previous prime is 1540544540387. The next prime is 1540544540443. The reversal of 1540544540441 is 1440454450451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 839019360400 + 701525180041 = 915980^2 + 837571^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1540544540441 is a prime.

Together with 1540544540443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1540544540443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770272270220 + 770272270221.

It is an arithmetic number, because the mean of its divisors is an integer number (770272270221).

Almost surely, 21540544540441 is an apocalyptic number.

It is an amenable number.

1540544540441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1540544540441 is an equidigital number, since it uses as much as digits as its factorization.

1540544540441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512000, while the sum is 41.

Adding to 1540544540441 its reverse (1440454450451), we get a palindrome (2980998990892).

The spelling of 1540544540441 in words is "one trillion, five hundred forty billion, five hundred forty-four million, five hundred forty thousand, four hundred forty-one".