Base | Representation |
---|---|
bin | 101101111011001… |
… | …0111110110011111 |
3 | 10222101121220100001 |
4 | 1123312113312133 |
5 | 11123442331002 |
6 | 412524315131 |
7 | 53121054301 |
oct | 13366276637 |
9 | 3871556301 |
10 | 1540980127 |
11 | 7209301a5 |
12 | 3700a2aa7 |
13 | 1b733cc7b |
14 | 10892d971 |
15 | 90441a87 |
hex | 5bd97d9f |
1540980127 has 2 divisors, whose sum is σ = 1540980128. Its totient is φ = 1540980126.
The previous prime is 1540980071. The next prime is 1540980131. The reversal of 1540980127 is 7210890451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1540980127 - 223 = 1532591519 is a prime.
It is a super-2 number, since 2×15409801272 = 4749239503617872258, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1540980157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770490063 + 770490064.
It is an arithmetic number, because the mean of its divisors is an integer number (770490064).
Almost surely, 21540980127 is an apocalyptic number.
1540980127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1540980127 is an equidigital number, since it uses as much as digits as its factorization.
1540980127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 37.
The square root of 1540980127 is about 39255.3197286686. The cubic root of 1540980127 is about 1155.0452877303.
The spelling of 1540980127 in words is "one billion, five hundred forty million, nine hundred eighty thousand, one hundred twenty-seven".
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