Base | Representation |
---|---|
bin | 10110011011001011000… |
… | …010000100111010011111 |
3 | 12110022121021001012202102 |
4 | 112123023002010322133 |
5 | 200221434140024411 |
6 | 3135532220515315 |
7 | 216222350034041 |
oct | 26331302047237 |
9 | 5408537035672 |
10 | 1541004611231 |
11 | 544599a24748 |
12 | 20a7a73abb3b |
13 | b241565bb87 |
14 | 54829425a91 |
15 | 2a142173d3b |
hex | 166cb084e9f |
1541004611231 has 2 divisors, whose sum is σ = 1541004611232. Its totient is φ = 1541004611230.
The previous prime is 1541004611227. The next prime is 1541004611261. The reversal of 1541004611231 is 1321164001451.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1541004611231 - 22 = 1541004611227 is a prime.
It is a super-2 number, since 2×15410046112312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1541004611194 and 1541004611203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1541004611261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770502305615 + 770502305616.
It is an arithmetic number, because the mean of its divisors is an integer number (770502305616).
Almost surely, 21541004611231 is an apocalyptic number.
1541004611231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541004611231 is an equidigital number, since it uses as much as digits as its factorization.
1541004611231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 1541004611231 its reverse (1321164001451), we get a palindrome (2862168612682).
The spelling of 1541004611231 in words is "one trillion, five hundred forty-one billion, four million, six hundred eleven thousand, two hundred thirty-one".
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