15412131104057 has 2 divisors, whose sum is σ = 15412131104058. Its totient is φ = 15412131104056.

The previous prime is 15412131103979. The next prime is 15412131104059. The reversal of 15412131104057 is 75040113121451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10539918082576 + 4872213021481 = 3246524^2 + 2207309^2 .

It is a cyclic number.

It is not a de Polignac number, because 15412131104057 - 2²⁶ = 15412063995193 is a prime.

Together with 15412131104059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (15412131104059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7706065552028 + 7706065552029.

It is an arithmetic number, because the mean of its divisors is an integer number (7706065552029).

Almost surely, 2^{15412131104057} is an apocalyptic number.

It is an amenable number.

15412131104057 is a deficient number, since it is larger than the sum of its proper divisors (1).

15412131104057 is an equidigital number, since it uses as much as digits as its factorization.

15412131104057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 35.

The spelling of 15412131104057 in words is "fifteen trillion, four hundred twelve billion, one hundred thirty-one million, one hundred four thousand, fifty-seven".