Base | Representation |
---|---|
bin | 10110011011011100111… |
… | …100001000000100111101 |
3 | 12110100101012100122012210 |
4 | 112123130330020010331 |
5 | 200223043042304323 |
6 | 3140022112051033 |
7 | 216232655454150 |
oct | 26333474100475 |
9 | 5410335318183 |
10 | 1541305041213 |
11 | 544733572193 |
12 | 20a86bb33a79 |
13 | b246297a5b2 |
14 | 548572abc97 |
15 | 2a15d71a293 |
hex | 166dcf0813d |
1541305041213 has 32 divisors (see below), whose sum is σ = 2429865676800. Its totient is φ = 850297404096.
The previous prime is 1541305041187. The next prime is 1541305041217. The reversal of 1541305041213 is 3121405031451.
It is not a de Polignac number, because 1541305041213 - 26 = 1541305041149 is a prime.
It is a super-2 number, since 2×15413050412132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1541305041217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6895318 + ... + 7115336.
It is an arithmetic number, because the mean of its divisors is an integer number (75933302400).
Almost surely, 21541305041213 is an apocalyptic number.
It is an amenable number.
1541305041213 is a deficient number, since it is larger than the sum of its proper divisors (888560635587).
1541305041213 is a wasteful number, since it uses less digits than its factorization.
1541305041213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 231561.
The product of its (nonzero) digits is 7200, while the sum is 30.
The spelling of 1541305041213 in words is "one trillion, five hundred forty-one billion, three hundred five million, forty-one thousand, two hundred thirteen".
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