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154134005535641 is a prime number
BaseRepresentation
bin100011000010111100011110…
…101001011101001110011001
3202012202001210212020000220102
4203002330132221131032121
5130200312420404120031
61303452103513505145
744315546226054365
oct4302743651351631
9665661725200812
10154134005535641
114512595695019a
12153542527121b5
136800a0b3483b1
142a0c1a8bba2a5
1512c45a4c187cb
hex8c2f1ea5d399

154134005535641 has 2 divisors, whose sum is σ = 154134005535642. Its totient is φ = 154134005535640.

The previous prime is 154134005535533. The next prime is 154134005535647. The reversal of 154134005535641 is 146535500431451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101290134490000 + 52843871045641 = 10064300^2 + 7269379^2 .

It is a cyclic number.

It is not a de Polignac number, because 154134005535641 - 218 = 154134005273497 is a prime.

It is a super-2 number, since 2×1541340055356412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (154134005535647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77067002767820 + 77067002767821.

It is an arithmetic number, because the mean of its divisors is an integer number (77067002767821).

Almost surely, 2154134005535641 is an apocalyptic number.

It is an amenable number.

154134005535641 is a deficient number, since it is larger than the sum of its proper divisors (1).

154134005535641 is an equidigital number, since it uses as much as digits as its factorization.

154134005535641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160000, while the sum is 47.

The spelling of 154134005535641 in words is "one hundred fifty-four trillion, one hundred thirty-four billion, five million, five hundred thirty-five thousand, six hundred forty-one".