Base | Representation |
---|---|
bin | 1000111110011101010… |
… | …1111010001010101011 |
3 | 112202000211011112100222 |
4 | 2033213111322022223 |
5 | 10011303003314111 |
6 | 154501343120255 |
7 | 14066230011416 |
oct | 2174725721253 |
9 | 482024145328 |
10 | 154205135531 |
11 | 5a441862777 |
12 | 25a76ba308b |
13 | 11706835835 |
14 | 766c062b7d |
15 | 4027d757db |
hex | 23e757a2ab |
154205135531 has 2 divisors, whose sum is σ = 154205135532. Its totient is φ = 154205135530.
The previous prime is 154205135503. The next prime is 154205135533. The reversal of 154205135531 is 135531502451.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-154205135531 is a prime.
It is a super-2 number, since 2×1542051355312 (a number of 23 digits) contains 22 as substring.
Together with 154205135533, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 154205135491 and 154205135500.
It is not a weakly prime, because it can be changed into another prime (154205135533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77102567765 + 77102567766.
It is an arithmetic number, because the mean of its divisors is an integer number (77102567766).
Almost surely, 2154205135531 is an apocalyptic number.
154205135531 is a deficient number, since it is larger than the sum of its proper divisors (1).
154205135531 is an equidigital number, since it uses as much as digits as its factorization.
154205135531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 35.
Adding to 154205135531 its reverse (135531502451), we get a palindrome (289736637982).
The spelling of 154205135531 in words is "one hundred fifty-four billion, two hundred five million, one hundred thirty-five thousand, five hundred thirty-one".
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