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1542123005231 is a prime number
BaseRepresentation
bin10110011100001101101…
…100011010010100101111
312110102111012111111220102
4112130031230122110233
5200231231442131411
63140235211541315
7216262150156664
oct26341554322457
95412435444812
101542123005231
11545013262706
1220aa59a5a83b
13b256327cc83
14548d3b91a6b
152a1aa43ed3b
hex1670db1a52f

1542123005231 has 2 divisors, whose sum is σ = 1542123005232. Its totient is φ = 1542123005230.

The previous prime is 1542123005191. The next prime is 1542123005239. The reversal of 1542123005231 is 1325003212451.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1542123005231 - 218 = 1542122743087 is a prime.

It is a super-2 number, since 2×15421230052312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1542123005194 and 1542123005203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1542123005239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771061502615 + 771061502616.

It is an arithmetic number, because the mean of its divisors is an integer number (771061502616).

Almost surely, 21542123005231 is an apocalyptic number.

1542123005231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1542123005231 is an equidigital number, since it uses as much as digits as its factorization.

1542123005231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1542123005231 its reverse (1325003212451), we get a palindrome (2867126217682).

The spelling of 1542123005231 in words is "one trillion, five hundred forty-two billion, one hundred twenty-three million, five thousand, two hundred thirty-one".