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154222113701 is a prime number
BaseRepresentation
bin1000111110100001011…
…0101011001110100101
3112202002000010010001002
42033220112223032211
510011321330114301
6154503151043045
714066524223435
oct2175026531645
9482060103032
10154222113701
115a4503a9717
1225a80810485
131170a1cb6a6
1476704022c5
1540295cb16b
hex23e85ab3a5

154222113701 has 2 divisors, whose sum is σ = 154222113702. Its totient is φ = 154222113700.

The previous prime is 154222113677. The next prime is 154222113713. The reversal of 154222113701 is 107311222451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114061552900 + 40160560801 = 337730^2 + 200401^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154222113701 is a prime.

It is a super-3 number, since 3×1542221137013 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154222113791) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77111056850 + 77111056851.

It is an arithmetic number, because the mean of its divisors is an integer number (77111056851).

Almost surely, 2154222113701 is an apocalyptic number.

It is an amenable number.

154222113701 is a deficient number, since it is larger than the sum of its proper divisors (1).

154222113701 is an equidigital number, since it uses as much as digits as its factorization.

154222113701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 29.

The spelling of 154222113701 in words is "one hundred fifty-four billion, two hundred twenty-two million, one hundred thirteen thousand, seven hundred one".