Base | Representation |
---|---|
bin | 10110011100010100000… |
… | …100111111101110000001 |
3 | 12110102202200001011100111 |
4 | 112130110010333232001 |
5 | 200231441402110103 |
6 | 3140253555351321 |
7 | 216264620444662 |
oct | 26342404775601 |
9 | 5412680034314 |
10 | 1542230113153 |
11 | 545068769454 |
12 | 20aa898b2541 |
13 | b257c511b42 |
14 | 549040b3369 |
15 | 2a1b4a4a86d |
hex | 1671413fb81 |
1542230113153 has 2 divisors, whose sum is σ = 1542230113154. Its totient is φ = 1542230113152.
The previous prime is 1542230113147. The next prime is 1542230113201. The reversal of 1542230113153 is 3513110322451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1537431364624 + 4798748529 = 1239932^2 + 69273^2 .
It is a cyclic number.
It is not a de Polignac number, because 1542230113153 - 25 = 1542230113121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1542230153153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771115056576 + 771115056577.
It is an arithmetic number, because the mean of its divisors is an integer number (771115056577).
Almost surely, 21542230113153 is an apocalyptic number.
It is an amenable number.
1542230113153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1542230113153 is an equidigital number, since it uses as much as digits as its factorization.
1542230113153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 1542230113153 in words is "one trillion, five hundred forty-two billion, two hundred thirty million, one hundred thirteen thousand, one hundred fifty-three".
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