Base | Representation |
---|---|
bin | 10110011100010100000… |
… | …100111111101110110001 |
3 | 12110102202200001011102021 |
4 | 112130110010333232301 |
5 | 200231441402110301 |
6 | 3140253555351441 |
7 | 216264620445061 |
oct | 26342404775661 |
9 | 5412680034367 |
10 | 1542230113201 |
11 | 545068769498 |
12 | 20aa898b2581 |
13 | b257c511b7b |
14 | 549040b33a1 |
15 | 2a1b4a4a8a1 |
hex | 1671413fbb1 |
1542230113201 has 2 divisors, whose sum is σ = 1542230113202. Its totient is φ = 1542230113200.
The previous prime is 1542230113153. The next prime is 1542230113223. The reversal of 1542230113201 is 1023110322451.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1515732784801 + 26497328400 = 1231151^2 + 162780^2 .
It is a cyclic number.
It is not a de Polignac number, because 1542230113201 - 225 = 1542196558769 is a prime.
It is not a weakly prime, because it can be changed into another prime (1542230113001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771115056600 + 771115056601.
It is an arithmetic number, because the mean of its divisors is an integer number (771115056601).
Almost surely, 21542230113201 is an apocalyptic number.
It is an amenable number.
1542230113201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1542230113201 is an equidigital number, since it uses as much as digits as its factorization.
1542230113201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1542230113201 its reverse (1023110322451), we get a palindrome (2565340435652).
The spelling of 1542230113201 in words is "one trillion, five hundred forty-two billion, two hundred thirty million, one hundred thirteen thousand, two hundred one".
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