154232520244141 has 2 divisors, whose sum is σ = 154232520244142. Its totient is φ = 154232520244140.

The previous prime is 154232520244037. The next prime is 154232520244241. The reversal of 154232520244141 is 141442025232451.

154232520244141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141345705432100 + 12886814812041 = 11888890^2 + 3589821^2 .

It is an emirp because it is prime and its reverse (141442025232451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 154232520244141 - 2¹¹ = 154232520242093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 154232520244094 and 154232520244103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (154232520244241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77116260122070 + 77116260122071.

It is an arithmetic number, because the mean of its divisors is an integer number (77116260122071).

Almost surely, 2^{154232520244141} is an apocalyptic number.

It is an amenable number.

154232520244141 is a deficient number, since it is larger than the sum of its proper divisors (1).

154232520244141 is an equidigital number, since it uses as much as digits as its factorization.

154232520244141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 307200, while the sum is 40.

Adding to 154232520244141 its reverse (141442025232451), we get a palindrome (295674545476592).

The spelling of 154232520244141 in words is "one hundred fifty-four trillion, two hundred thirty-two billion, five hundred twenty million, two hundred forty-four thousand, one hundred forty-one".