Base | Representation |
---|---|
bin | 1110000010001011001010… |
… | …1010111011001101010001 |
3 | 2000122010212110220200221021 |
4 | 3200202302222323031101 |
5 | 4010303201122433431 |
6 | 52452403313555441 |
7 | 3151550446650505 |
oct | 340426252731521 |
9 | 60563773820837 |
10 | 15430520124241 |
11 | 4a0a057378a52 |
12 | 1892655b75b81 |
13 | 87c126902b21 |
14 | 3b4bac1d6305 |
15 | 1bb5b3677b11 |
hex | e08b2abb351 |
15430520124241 has 2 divisors, whose sum is σ = 15430520124242. Its totient is φ = 15430520124240.
The previous prime is 15430520124233. The next prime is 15430520124247. The reversal of 15430520124241 is 14242102503451.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15256523521600 + 173996602641 = 3905960^2 + 417129^2 .
It is a cyclic number.
It is not a de Polignac number, because 15430520124241 - 23 = 15430520124233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15430520124197 and 15430520124206.
It is not a weakly prime, because it can be changed into another prime (15430520124247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7715260062120 + 7715260062121.
It is an arithmetic number, because the mean of its divisors is an integer number (7715260062121).
Almost surely, 215430520124241 is an apocalyptic number.
It is an amenable number.
15430520124241 is a deficient number, since it is larger than the sum of its proper divisors (1).
15430520124241 is an equidigital number, since it uses as much as digits as its factorization.
15430520124241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 15430520124241 its reverse (14242102503451), we get a palindrome (29672622627692).
The spelling of 15430520124241 in words is "fifteen trillion, four hundred thirty billion, five hundred twenty million, one hundred twenty-four thousand, two hundred forty-one".
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