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15434134132031 is a prime number
BaseRepresentation
bin1110000010011000101000…
…0101010001010100111111
32000122111012100022022121122
43200212022011101110333
54010333101314211111
652454202054421155
73152036142343406
oct340461205212477
960574170268548
1015434134132031
114a1064139454a
1218932a43617bb
1387c581578a84
143b503219063d
151bb725aa4cdb
hexe098a15153f

15434134132031 has 2 divisors, whose sum is σ = 15434134132032. Its totient is φ = 15434134132030.

The previous prime is 15434134131989. The next prime is 15434134132057. The reversal of 15434134132031 is 13023143143451.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15434134132031 - 26 = 15434134131967 is a prime.

It is a super-2 number, since 2×154341341320312 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 15434134131982 and 15434134132000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15434134132091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7717067066015 + 7717067066016.

It is an arithmetic number, because the mean of its divisors is an integer number (7717067066016).

Almost surely, 215434134132031 is an apocalyptic number.

15434134132031 is a deficient number, since it is larger than the sum of its proper divisors (1).

15434134132031 is an equidigital number, since it uses as much as digits as its factorization.

15434134132031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 15434134132031 its reverse (13023143143451), we get a palindrome (28457277275482).

The spelling of 15434134132031 in words is "fifteen trillion, four hundred thirty-four billion, one hundred thirty-four million, one hundred thirty-two thousand, thirty-one".