Base | Representation |
---|---|
bin | 10110011101011011010… |
… | …111000100011001011001 |
3 | 12110112212000101012022002 |
4 | 112131123113010121121 |
5 | 200241414031030431 |
6 | 3141012400210345 |
7 | 216336351551321 |
oct | 26353327043131 |
9 | 5415760335262 |
10 | 1543426033241 |
11 | 545621838964 |
12 | 20b1623099b5 |
13 | b2710208271 |
14 | 549b8c60281 |
15 | 2a234a2c3cb |
hex | 1675b5c4659 |
1543426033241 has 2 divisors, whose sum is σ = 1543426033242. Its totient is φ = 1543426033240.
The previous prime is 1543426033183. The next prime is 1543426033313. The reversal of 1543426033241 is 1423306243451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088099334400 + 455326698841 = 1043120^2 + 674779^2 .
It is an emirp because it is prime and its reverse (1423306243451) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1543426033241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1543426033195 and 1543426033204.
It is not a weakly prime, because it can be changed into another prime (1543426033741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771713016620 + 771713016621.
It is an arithmetic number, because the mean of its divisors is an integer number (771713016621).
Almost surely, 21543426033241 is an apocalyptic number.
It is an amenable number.
1543426033241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1543426033241 is an equidigital number, since it uses as much as digits as its factorization.
1543426033241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 38.
The spelling of 1543426033241 in words is "one trillion, five hundred forty-three billion, four hundred twenty-six million, thirty-three thousand, two hundred forty-one".
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