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15435001011401 is a prime number
BaseRepresentation
bin1110000010011011110111…
…0000001001110011001001
32000122120102202111100112222
43200212331300021303021
54010341340224331101
652454424102543425
73152066466605456
oct340467560116311
960576382440488
1015435001011401
114a10a46754884
1218934a6737b75
1387c68c046c4a
143b50b536882d
151bb776c3d01b
hexe09bdc09cc9

15435001011401 has 2 divisors, whose sum is σ = 15435001011402. Its totient is φ = 15435001011400.

The previous prime is 15435001011359. The next prime is 15435001011427. The reversal of 15435001011401 is 10411010053451.

It is an a-pointer prime, because the next prime (15435001011427) can be obtained adding 15435001011401 to its sum of digits (26).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13923942990400 + 1511058021001 = 3731480^2 + 1229251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15435001011401 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (15435001019401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7717500505700 + 7717500505701.

It is an arithmetic number, because the mean of its divisors is an integer number (7717500505701).

Almost surely, 215435001011401 is an apocalyptic number.

It is an amenable number.

15435001011401 is a deficient number, since it is larger than the sum of its proper divisors (1).

15435001011401 is an equidigital number, since it uses as much as digits as its factorization.

15435001011401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 15435001011401 its reverse (10411010053451), we get a palindrome (25846011064852).

The spelling of 15435001011401 in words is "fifteen trillion, four hundred thirty-five billion, one million, eleven thousand, four hundred one".