Search a number
-
+
1544405051381 is a prime number
BaseRepresentation
bin10110011110010101101…
…101101110011111110101
312110122101020120110201012
4112132111231232133311
5200300420143121011
63141253452042005
7216402540223523
oct26362555563765
95418336513635
101544405051381
11545a84430765
1220b396163305
13b2837caa13a
1454a6cca9313
152a290966a8b
hex16795b6e7f5

1544405051381 has 2 divisors, whose sum is σ = 1544405051382. Its totient is φ = 1544405051380.

The previous prime is 1544405051341. The next prime is 1544405051389. The reversal of 1544405051381 is 1831505044451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1435045868356 + 109359183025 = 1197934^2 + 330695^2 .

It is an emirp because it is prime and its reverse (1831505044451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1544405051381 - 218 = 1544404789237 is a prime.

It is a super-2 number, since 2×15444050513812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1544405051389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 772202525690 + 772202525691.

It is an arithmetic number, because the mean of its divisors is an integer number (772202525691).

Almost surely, 21544405051381 is an apocalyptic number.

It is an amenable number.

1544405051381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1544405051381 is an equidigital number, since it uses as much as digits as its factorization.

1544405051381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192000, while the sum is 41.

The spelling of 1544405051381 in words is "one trillion, five hundred forty-four billion, four hundred five million, fifty-one thousand, three hundred eighty-one".