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154611023325113 is a prime number
BaseRepresentation
bin100011001001111000101111…
…000111111010011110111001
3202021102200002001100111010102
4203021320233013322132321
5130231121333432400423
61304455153520325145
744365164201265565
oct4311705707723671
9667380061314112
10154611023325113
114529a191a69773
121541079aa737b5
1368369abcc5214
142a272dba226a5
1512d1bc2da2c28
hex8c9e2f1fa7b9

154611023325113 has 2 divisors, whose sum is σ = 154611023325114. Its totient is φ = 154611023325112.

The previous prime is 154611023325103. The next prime is 154611023325131. The reversal of 154611023325113 is 311523320116451.

Together with next prime (154611023325131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95388194489344 + 59222828835769 = 9766688^2 + 7695637^2 .

It is a cyclic number.

It is not a de Polignac number, because 154611023325113 - 232 = 154606728357817 is a prime.

It is a super-2 number, since 2×1546110233251132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (154611023325103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77305511662556 + 77305511662557.

It is an arithmetic number, because the mean of its divisors is an integer number (77305511662557).

Almost surely, 2154611023325113 is an apocalyptic number.

It is an amenable number.

154611023325113 is a deficient number, since it is larger than the sum of its proper divisors (1).

154611023325113 is an equidigital number, since it uses as much as digits as its factorization.

154611023325113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 154611023325113 in words is "one hundred fifty-four trillion, six hundred eleven billion, twenty-three million, three hundred twenty-five thousand, one hundred thirteen".