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15493165139033 is a prime number
BaseRepresentation
bin1110000101110100100010…
…0110101100010001011001
32000212010120022120011212022
43201131020212230101121
54012320000233422113
652541243430024225
73156226034541551
oct341351046542131
960763508504768
1015493165139033
114a336838a684a
1218a28197a8075
13884ccb33420a
143b7c32088161
151bd02d1ed908
hexe17489ac459

15493165139033 has 2 divisors, whose sum is σ = 15493165139034. Its totient is φ = 15493165139032.

The previous prime is 15493165139009. The next prime is 15493165139041. The reversal of 15493165139033 is 33093156139451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10631329767184 + 4861835371849 = 3260572^2 + 2204957^2 .

It is an emirp because it is prime and its reverse (33093156139451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15493165139033 - 240 = 14393653511257 is a prime.

It is not a weakly prime, because it can be changed into another prime (15493165139633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7746582569516 + 7746582569517.

It is an arithmetic number, because the mean of its divisors is an integer number (7746582569517).

Almost surely, 215493165139033 is an apocalyptic number.

It is an amenable number.

15493165139033 is a deficient number, since it is larger than the sum of its proper divisors (1).

15493165139033 is an equidigital number, since it uses as much as digits as its factorization.

15493165139033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3936600, while the sum is 53.

The spelling of 15493165139033 in words is "fifteen trillion, four hundred ninety-three billion, one hundred sixty-five million, one hundred thirty-nine thousand, thirty-three".