Base | Representation |
---|---|
bin | 11100110111010011… |
… | …10011101101100001 |
3 | 1110222222002010120011 |
4 | 32123221303231201 |
5 | 223214030030311 |
6 | 11041404044521 |
7 | 1056004426621 |
oct | 163351635541 |
9 | 43888063504 |
10 | 15496330081 |
11 | 6632302171 |
12 | 3005833741 |
13 | 15cc6178ab |
14 | a70102881 |
15 | 60a6a5321 |
hex | 39ba73b61 |
15496330081 has 2 divisors, whose sum is σ = 15496330082. Its totient is φ = 15496330080.
The previous prime is 15496330079. The next prime is 15496330219. The reversal of 15496330081 is 18003369451.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11276528481 + 4219801600 = 106191^2 + 64960^2 .
It is a cyclic number.
It is not a de Polignac number, because 15496330081 - 21 = 15496330079 is a prime.
It is a super-2 number, since 2×154963300812 (a number of 21 digits) contains 22 as substring.
Together with 15496330079, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (15496330021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7748165040 + 7748165041.
It is an arithmetic number, because the mean of its divisors is an integer number (7748165041).
Almost surely, 215496330081 is an apocalyptic number.
It is an amenable number.
15496330081 is a deficient number, since it is larger than the sum of its proper divisors (1).
15496330081 is an equidigital number, since it uses as much as digits as its factorization.
15496330081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 15496330081 in words is "fifteen billion, four hundred ninety-six million, three hundred thirty thousand, eighty-one".
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