Base | Representation |
---|---|
bin | 100011001111100110001011… |
… | …011100010111111011010111 |
3 | 202022211011220110001002021021 |
4 | 203033212023130113323113 |
5 | 130304033443014411112 |
6 | 1305355330243102011 |
7 | 44435425046653321 |
oct | 4317461334277327 |
9 | 668734813032237 |
10 | 155003414216407 |
11 | 45430640438079 |
12 | 15474849971907 |
13 | 68649b4092a73 |
14 | 2a3c2c33d0611 |
15 | 12dbedb765907 |
hex | 8cf98b717ed7 |
155003414216407 has 2 divisors, whose sum is σ = 155003414216408. Its totient is φ = 155003414216406.
The previous prime is 155003414216401. The next prime is 155003414216429. The reversal of 155003414216407 is 704612414300551.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 155003414216407 - 243 = 146207321194199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155003414216401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77501707108203 + 77501707108204.
It is an arithmetic number, because the mean of its divisors is an integer number (77501707108204).
Almost surely, 2155003414216407 is an apocalyptic number.
155003414216407 is a deficient number, since it is larger than the sum of its proper divisors (1).
155003414216407 is an equidigital number, since it uses as much as digits as its factorization.
155003414216407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 43.
Adding to 155003414216407 its reverse (704612414300551), we get a palindrome (859615828516958).
The spelling of 155003414216407 in words is "one hundred fifty-five trillion, three billion, four hundred fourteen million, two hundred sixteen thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •