Base | Representation |
---|---|
bin | 10110100011101011001… |
… | …101001101101000011011 |
3 | 12111012011112020021201211 |
4 | 112203223031031220123 |
5 | 200344133342223102 |
6 | 3144042154323551 |
7 | 216664526311354 |
oct | 26435315155033 |
9 | 5435145207654 |
10 | 1550134336027 |
11 | 54845446a052 |
12 | 210514a295b7 |
13 | b323bc5c5b4 |
14 | 55053b68d2b |
15 | 2a4c89277d7 |
hex | 168eb34da1b |
1550134336027 has 2 divisors, whose sum is σ = 1550134336028. Its totient is φ = 1550134336026.
The previous prime is 1550134335979. The next prime is 1550134336073. The reversal of 1550134336027 is 7206334310551.
It is a strong prime.
It is an emirp because it is prime and its reverse (7206334310551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1550134336027 - 27 = 1550134335899 is a prime.
It is not a weakly prime, because it can be changed into another prime (1550134336097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775067168013 + 775067168014.
It is an arithmetic number, because the mean of its divisors is an integer number (775067168014).
Almost surely, 21550134336027 is an apocalyptic number.
1550134336027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1550134336027 is an equidigital number, since it uses as much as digits as its factorization.
1550134336027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 40.
Adding to 1550134336027 its reverse (7206334310551), we get a palindrome (8756468646578).
The spelling of 1550134336027 in words is "one trillion, five hundred fifty billion, one hundred thirty-four million, three hundred thirty-six thousand, twenty-seven".
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