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1550134336073 is a prime number
BaseRepresentation
bin10110100011101011001…
…101001101101001001001
312111012011112020021210112
4112203223031031221021
5200344133342223243
63144042154324105
7216664526311451
oct26435315155111
95435145207715
101550134336073
1154845446a094
12210514a29635
13b323bc5c61b
1455053b68d61
152a4c8927818
hex168eb34da49

1550134336073 has 2 divisors, whose sum is σ = 1550134336074. Its totient is φ = 1550134336072.

The previous prime is 1550134336027. The next prime is 1550134336097. The reversal of 1550134336073 is 3706334310551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1273539334144 + 276595001929 = 1128512^2 + 525923^2 .

It is a cyclic number.

It is not a de Polignac number, because 1550134336073 - 210 = 1550134335049 is a prime.

It is a super-3 number, since 3×15501343360733 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1550134336073.

It is not a weakly prime, because it can be changed into another prime (1550134336573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775067168036 + 775067168037.

It is an arithmetic number, because the mean of its divisors is an integer number (775067168037).

Almost surely, 21550134336073 is an apocalyptic number.

It is an amenable number.

1550134336073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1550134336073 is an equidigital number, since it uses as much as digits as its factorization.

1550134336073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 340200, while the sum is 41.

The spelling of 1550134336073 in words is "one trillion, five hundred fifty billion, one hundred thirty-four million, three hundred thirty-six thousand, seventy-three".