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15503120130 = 235516770671
BaseRepresentation
bin11100111000000111…
…01101011100000010
31111000102212002202110
432130003231130002
5223222244321010
611042205400150
71056116226651
oct163403553402
944012762673
1015503120130
11663611a683
123007b69056
131600b54384
14a70d8d198
1560b097120
hex39c0ed702

15503120130 has 16 divisors (see below), whose sum is σ = 37207488384. Its totient is φ = 4134165360.

The previous prime is 15503120107. The next prime is 15503120159. The reversal of 15503120130 is 3102130551.

It is a super-2 number, since 2×155031201302 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15503120097 and 15503120106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 258385306 + ... + 258385365.

It is an arithmetic number, because the mean of its divisors is an integer number (2325468024).

Almost surely, 215503120130 is an apocalyptic number.

15503120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

15503120130 is an abundant number, since it is smaller than the sum of its proper divisors (21704368254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

15503120130 is a wasteful number, since it uses less digits than its factorization.

15503120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 516770681.

The product of its (nonzero) digits is 450, while the sum is 21.

Adding to 15503120130 its reverse (3102130551), we get a palindrome (18605250681).

The spelling of 15503120130 in words is "fifteen billion, five hundred three million, one hundred twenty thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 516770671 1033541342 1550312013 2583853355 3100624026 5167706710 7751560065 15503120130