Base | Representation |
---|---|
bin | 11100111000000111… |
… | …01101011100000010 |
3 | 1111000102212002202110 |
4 | 32130003231130002 |
5 | 223222244321010 |
6 | 11042205400150 |
7 | 1056116226651 |
oct | 163403553402 |
9 | 44012762673 |
10 | 15503120130 |
11 | 663611a683 |
12 | 3007b69056 |
13 | 1600b54384 |
14 | a70d8d198 |
15 | 60b097120 |
hex | 39c0ed702 |
15503120130 has 16 divisors (see below), whose sum is σ = 37207488384. Its totient is φ = 4134165360.
The previous prime is 15503120107. The next prime is 15503120159. The reversal of 15503120130 is 3102130551.
It is a super-2 number, since 2×155031201302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15503120097 and 15503120106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 258385306 + ... + 258385365.
It is an arithmetic number, because the mean of its divisors is an integer number (2325468024).
Almost surely, 215503120130 is an apocalyptic number.
15503120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
15503120130 is an abundant number, since it is smaller than the sum of its proper divisors (21704368254).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15503120130 is a wasteful number, since it uses less digits than its factorization.
15503120130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 516770681.
The product of its (nonzero) digits is 450, while the sum is 21.
Adding to 15503120130 its reverse (3102130551), we get a palindrome (18605250681).
The spelling of 15503120130 in words is "fifteen billion, five hundred three million, one hundred twenty thousand, one hundred thirty".
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