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155066566006117 is a prime number
BaseRepresentation
bin100011010000100000111111…
…100101010101010101100101
3202100001012220121021101200201
4203100200333211111111211
5130311102311344143432
61305444332541110501
744443122030216313
oct4320407745252545
9670035817241621
10155066566006117
11454553a7a2a417
1215484b33258431
13686a9397abb7c
142a413946bd0b3
1512dd985a41ee7
hex8d083f955565

155066566006117 has 2 divisors, whose sum is σ = 155066566006118. Its totient is φ = 155066566006116.

The previous prime is 155066566006019. The next prime is 155066566006159. The reversal of 155066566006117 is 711600665660551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 150071099623201 + 4995466382916 = 12250351^2 + 2235054^2 .

It is an emirp because it is prime and its reverse (711600665660551) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 155066566006117 - 243 = 146270472983909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155066566006217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77533283003058 + 77533283003059.

It is an arithmetic number, because the mean of its divisors is an integer number (77533283003059).

Almost surely, 2155066566006117 is an apocalyptic number.

It is an amenable number.

155066566006117 is a deficient number, since it is larger than the sum of its proper divisors (1).

155066566006117 is an equidigital number, since it uses as much as digits as its factorization.

155066566006117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804000, while the sum is 55.

The spelling of 155066566006117 in words is "one hundred fifty-five trillion, sixty-six billion, five hundred sixty-six million, six thousand, one hundred seventeen".