Base | Representation |
---|---|
bin | 10110100100100101000… |
… | …001110101000010101011 |
3 | 12111021200010122011211112 |
4 | 112210211001311002223 |
5 | 200403130213232001 |
6 | 3144322331020535 |
7 | 220030546055405 |
oct | 26444501650253 |
9 | 5437603564745 |
10 | 1551104430251 |
11 | 548902017212 |
12 | 21074589a74b |
13 | b3364c2864c |
14 | 5510692db75 |
15 | 2a533b9ccbb |
hex | 169250750ab |
1551104430251 has 2 divisors, whose sum is σ = 1551104430252. Its totient is φ = 1551104430250.
The previous prime is 1551104430233. The next prime is 1551104430257. The reversal of 1551104430251 is 1520344011551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1551104430251 - 214 = 1551104413867 is a prime.
It is not a weakly prime, because it can be changed into another prime (1551104430257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775552215125 + 775552215126.
It is an arithmetic number, because the mean of its divisors is an integer number (775552215126).
Almost surely, 21551104430251 is an apocalyptic number.
1551104430251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1551104430251 is an equidigital number, since it uses as much as digits as its factorization.
1551104430251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 1551104430251 in words is "one trillion, five hundred fifty-one billion, one hundred four million, four hundred thirty thousand, two hundred fifty-one".
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