Base | Representation |
---|---|
bin | 100011010001001100101010… |
… | …011010100110011000011011 |
3 | 202100012200221102011001021012 |
4 | 203101030222122212120123 |
5 | 130312334324102323232 |
6 | 1305522045430004135 |
7 | 44446402012353344 |
oct | 4321145232463033 |
9 | 670180842131235 |
10 | 155113455511067 |
11 | 454732799224a9 |
12 | 1549203a4a664b |
13 | 687219ccba881 |
14 | 2a43761c830cb |
15 | 12deccc2b89b2 |
hex | 8d132a6a661b |
155113455511067 has 2 divisors, whose sum is σ = 155113455511068. Its totient is φ = 155113455511066.
The previous prime is 155113455510991. The next prime is 155113455511073. The reversal of 155113455511067 is 760115554311551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 155113455511067 - 210 = 155113455510043 is a prime.
It is a super-2 number, since 2×1551134555110672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (155113455511087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77556727755533 + 77556727755534.
It is an arithmetic number, because the mean of its divisors is an integer number (77556727755534).
Almost surely, 2155113455511067 is an apocalyptic number.
155113455511067 is a deficient number, since it is larger than the sum of its proper divisors (1).
155113455511067 is an equidigital number, since it uses as much as digits as its factorization.
155113455511067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1575000, while the sum is 50.
The spelling of 155113455511067 in words is "one hundred fifty-five trillion, one hundred thirteen billion, four hundred fifty-five million, five hundred eleven thousand, sixty-seven".
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