Base | Representation |
---|---|
bin | 100011010001001100101010… |
… | …011010100110010111001111 |
3 | 202100012200221102011001011101 |
4 | 203101030222122212113033 |
5 | 130312334324102322431 |
6 | 1305522045430003531 |
7 | 44446402012353205 |
oct | 4321145232462717 |
9 | 670180842131141 |
10 | 155113455510991 |
11 | 4547327992243a |
12 | 1549203a4a65a7 |
13 | 687219ccba823 |
14 | 2a43761c83075 |
15 | 12deccc2b8961 |
hex | 8d132a6a65cf |
155113455510991 has 2 divisors, whose sum is σ = 155113455510992. Its totient is φ = 155113455510990.
The previous prime is 155113455510929. The next prime is 155113455511067. The reversal of 155113455510991 is 199015554311551.
155113455510991 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 155113455510991 - 217 = 155113455379919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155113455570991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77556727755495 + 77556727755496.
It is an arithmetic number, because the mean of its divisors is an integer number (77556727755496).
Almost surely, 2155113455510991 is an apocalyptic number.
155113455510991 is a deficient number, since it is larger than the sum of its proper divisors (1).
155113455510991 is an equidigital number, since it uses as much as digits as its factorization.
155113455510991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3037500, while the sum is 55.
The spelling of 155113455510991 in words is "one hundred fifty-five trillion, one hundred thirteen billion, four hundred fifty-five million, five hundred ten thousand, nine hundred ninety-one".
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