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155115004013 is a prime number
BaseRepresentation
bin1001000001110110010…
…0110010000001101101
3112211101020020122021122
42100131210302001231
510020133420112023
6155131524510325
714130615531254
oct2203544620155
9484336218248
10155115004013
115a8694153a2
122608b84b3a5
13118201a5c58
147716c2b79b
15407cba12c8
hex241d93206d

155115004013 has 2 divisors, whose sum is σ = 155115004014. Its totient is φ = 155115004012.

The previous prime is 155115003991. The next prime is 155115004027. The reversal of 155115004013 is 310400511551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118503243049 + 36611760964 = 344243^2 + 191342^2 .

It is a cyclic number.

It is not a de Polignac number, because 155115004013 - 212 = 155114999917 is a prime.

It is a super-2 number, since 2×1551150040132 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155115004813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77557502006 + 77557502007.

It is an arithmetic number, because the mean of its divisors is an integer number (77557502007).

Almost surely, 2155115004013 is an apocalyptic number.

It is an amenable number.

155115004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

155115004013 is an equidigital number, since it uses as much as digits as its factorization.

155115004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 155115004013 its reverse (310400511551), we get a palindrome (465515515564).

The spelling of 155115004013 in words is "one hundred fifty-five billion, one hundred fifteen million, four thousand, thirteen".