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155121241140413 is a prime number
BaseRepresentation
bin100011010001010011111010…
…011110011010110010111101
3202100020110001000011222220122
4203101103322132122302331
5130313001300212443123
61305525414151024325
744450065651204232
oct4321237236326275
9670213030158818
10155121241140413
1145476604692019
121549365196b0a5
136872b40cb4642
142a43c9dca7789
1512e00d5a6bbc8
hex8d14fa79acbd

155121241140413 has 2 divisors, whose sum is σ = 155121241140414. Its totient is φ = 155121241140412.

The previous prime is 155121241140407. The next prime is 155121241140451. The reversal of 155121241140413 is 314041142121551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144409779111844 + 10711462028569 = 12017062^2 + 3272837^2 .

It is a cyclic number.

It is not a de Polignac number, because 155121241140413 - 218 = 155121240878269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155121241140403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77560620570206 + 77560620570207.

It is an arithmetic number, because the mean of its divisors is an integer number (77560620570207).

Almost surely, 2155121241140413 is an apocalyptic number.

It is an amenable number.

155121241140413 is a deficient number, since it is larger than the sum of its proper divisors (1).

155121241140413 is an equidigital number, since it uses as much as digits as its factorization.

155121241140413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 35.

Adding to 155121241140413 its reverse (314041142121551), we get a palindrome (469162383261964).

The spelling of 155121241140413 in words is "one hundred fifty-five trillion, one hundred twenty-one billion, two hundred forty-one million, one hundred forty thousand, four hundred thirteen".