Base | Representation |
---|---|
bin | 1110000110111110100000… |
… | …0100101010010110011011 |
3 | 2000221000211001211002010002 |
4 | 3201233220010222112123 |
5 | 4013131131213121021 |
6 | 52554325550043215 |
7 | 3160531052043341 |
oct | 341575004522633 |
9 | 60830731732102 |
10 | 15513020442011 |
11 | 4a41042685854 |
12 | 18a663b1a950b |
13 | 886b43a488c1 |
14 | 3b8b97065991 |
15 | 1bd7e13d650b |
hex | e1be812a59b |
15513020442011 has 2 divisors, whose sum is σ = 15513020442012. Its totient is φ = 15513020442010.
The previous prime is 15513020441983. The next prime is 15513020442037. The reversal of 15513020442011 is 11024402031551.
It is a happy number.
15513020442011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15513020442011 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (15513020448011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7756510221005 + 7756510221006.
It is an arithmetic number, because the mean of its divisors is an integer number (7756510221006).
Almost surely, 215513020442011 is an apocalyptic number.
15513020442011 is a deficient number, since it is larger than the sum of its proper divisors (1).
15513020442011 is an equidigital number, since it uses as much as digits as its factorization.
15513020442011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 15513020442011 its reverse (11024402031551), we get a palindrome (26537422473562).
The spelling of 15513020442011 in words is "fifteen trillion, five hundred thirteen billion, twenty million, four hundred forty-two thousand, eleven".
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