Base | Representation |
---|---|
bin | 1001000010001101111… |
… | …0111101001011100011 |
3 | 112211122010210021110201 |
4 | 2100203132331023203 |
5 | 10020334304441011 |
6 | 155145425410031 |
7 | 14133231264661 |
oct | 2204336751343 |
9 | 484563707421 |
10 | 155214140131 |
11 | 5a90a376876 |
12 | 260b8a99917 |
13 | 118378a648b |
14 | 7726075c31 |
15 | 4086734cc1 |
hex | 24237bd2e3 |
155214140131 has 2 divisors, whose sum is σ = 155214140132. Its totient is φ = 155214140130.
The previous prime is 155214140101. The next prime is 155214140143. The reversal of 155214140131 is 131041412551.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 155214140131 - 213 = 155214131939 is a prime.
It is a super-2 number, since 2×1552141401312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 155214140131.
It is not a weakly prime, because it can be changed into another prime (155214140101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77607070065 + 77607070066.
It is an arithmetic number, because the mean of its divisors is an integer number (77607070066).
Almost surely, 2155214140131 is an apocalyptic number.
155214140131 is a deficient number, since it is larger than the sum of its proper divisors (1).
155214140131 is an equidigital number, since it uses as much as digits as its factorization.
155214140131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 155214140131 its reverse (131041412551), we get a palindrome (286255552682).
The spelling of 155214140131 in words is "one hundred fifty-five billion, two hundred fourteen million, one hundred forty thousand, one hundred thirty-one".
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