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155240132043551 is a prime number
BaseRepresentation
bin100011010011000010101000…
…111011001110001100011111
3202100122210220201101122112112
4203103002220323032030133
5130321423242300343201
61310100155423424235
744461505122205132
oct4323025073161437
9670583821348475
10155240132043551
1145511a74489265
12154b26b215507b
13688110a484579
142a4993bbc4219
1512e32434910bb
hex8d30a8ece31f

155240132043551 has 2 divisors, whose sum is σ = 155240132043552. Its totient is φ = 155240132043550.

The previous prime is 155240132043547. The next prime is 155240132043559. The reversal of 155240132043551 is 155340231042551.

155240132043551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 155240132043551 - 22 = 155240132043547 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 155240132043499 and 155240132043508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155240132043559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77620066021775 + 77620066021776.

It is an arithmetic number, because the mean of its divisors is an integer number (77620066021776).

Almost surely, 2155240132043551 is an apocalyptic number.

155240132043551 is a deficient number, since it is larger than the sum of its proper divisors (1).

155240132043551 is an equidigital number, since it uses as much as digits as its factorization.

155240132043551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 41.

The spelling of 155240132043551 in words is "one hundred fifty-five trillion, two hundred forty billion, one hundred thirty-two million, forty-three thousand, five hundred fifty-one".