Base | Representation |
---|---|
bin | 10110100110010111010… |
… | …110000011100010011011 |
3 | 12111110121210111211201121 |
4 | 112212113112003202123 |
5 | 200421042204211011 |
6 | 3145240522230111 |
7 | 220126225020001 |
oct | 26462726034233 |
9 | 5443553454647 |
10 | 1553022335131 |
11 | 5496a6691573 |
12 | 210ba0055337 |
13 | b35ac38aac7 |
14 | 55249538a71 |
15 | 2a5e7245e71 |
hex | 1699758389b |
1553022335131 has 2 divisors, whose sum is σ = 1553022335132. Its totient is φ = 1553022335130.
The previous prime is 1553022335087. The next prime is 1553022335203. The reversal of 1553022335131 is 1315332203551.
It is a weak prime.
It is an emirp because it is prime and its reverse (1315332203551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1553022335131 - 237 = 1415583381659 is a prime.
It is a super-2 number, since 2×15530223351312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1553022335531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776511167565 + 776511167566.
It is an arithmetic number, because the mean of its divisors is an integer number (776511167566).
Almost surely, 21553022335131 is an apocalyptic number.
1553022335131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1553022335131 is an equidigital number, since it uses as much as digits as its factorization.
1553022335131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 1553022335131 its reverse (1315332203551), we get a palindrome (2868354538682).
The spelling of 1553022335131 in words is "one trillion, five hundred fifty-three billion, twenty-two million, three hundred thirty-five thousand, one hundred thirty-one".
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