Base | Representation |
---|---|
bin | 1001000010111100111… |
… | …1001011001111001001 |
3 | 112212010212211120002221 |
4 | 2100233033023033021 |
5 | 10021240300024433 |
6 | 155221152054041 |
7 | 14141144336353 |
oct | 2205717131711 |
9 | 485125746087 |
10 | 155411329993 |
11 | 5aa0070a4a7 |
12 | 26152b34321 |
13 | 118696b867a |
14 | 77443260d3 |
15 | 4098bd672d |
hex | 242f3cb3c9 |
155411329993 has 2 divisors, whose sum is σ = 155411329994. Its totient is φ = 155411329992.
The previous prime is 155411329967. The next prime is 155411329999. The reversal of 155411329993 is 399923114551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102817705104 + 52593624889 = 320652^2 + 229333^2 .
It is a cyclic number.
It is not a de Polignac number, because 155411329993 - 25 = 155411329961 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 155411329993.
It is not a weakly prime, because it can be changed into another prime (155411329999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77705664996 + 77705664997.
It is an arithmetic number, because the mean of its divisors is an integer number (77705664997).
Almost surely, 2155411329993 is an apocalyptic number.
It is an amenable number.
155411329993 is a deficient number, since it is larger than the sum of its proper divisors (1).
155411329993 is an equidigital number, since it uses as much as digits as its factorization.
155411329993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1312200, while the sum is 52.
The spelling of 155411329993 in words is "one hundred fifty-five billion, four hundred eleven million, three hundred twenty-nine thousand, nine hundred ninety-three".
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