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155421204031 is a prime number
BaseRepresentation
bin1001000010111111010…
…0110101111000111111
3112212011120102012202001
42100233310311320333
510021300312012111
6155222143443131
714141324302552
oct2205764657077
9485146365661
10155421204031
115aa06243a65
12261562b64a7
131186b764ab2
147745776699
1540999d71c1
hex242fd35e3f

155421204031 has 2 divisors, whose sum is σ = 155421204032. Its totient is φ = 155421204030.

The previous prime is 155421204017. The next prime is 155421204067. The reversal of 155421204031 is 130402124551.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 155421204031 - 29 = 155421203519 is a prime.

It is a super-2 number, since 2×1554212040312 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155421204091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77710602015 + 77710602016.

It is an arithmetic number, because the mean of its divisors is an integer number (77710602016).

Almost surely, 2155421204031 is an apocalyptic number.

155421204031 is a deficient number, since it is larger than the sum of its proper divisors (1).

155421204031 is an equidigital number, since it uses as much as digits as its factorization.

155421204031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 155421204031 its reverse (130402124551), we get a palindrome (285823328582).

The spelling of 155421204031 in words is "one hundred fifty-five billion, four hundred twenty-one million, two hundred four thousand, thirty-one".