Base | Representation |
---|---|
bin | 100011010101110110011001… |
… | …011010000110011111000100 |
3 | 202101100021010010202111102211 |
4 | 203111312121122012133010 |
5 | 130333104040134400200 |
6 | 1310325000130113204 |
7 | 44511450144220126 |
oct | 4325663132063704 |
9 | 671307103674384 |
10 | 155433145231300 |
11 | 45586910392a62 |
12 | 15523b99a1b804 |
13 | 689638a1372c1 |
14 | 2a5500bdbd216 |
15 | 12e828d353aba |
hex | 8d5d996867c4 |
155433145231300 has 72 divisors (see below), whose sum is σ = 339298997330216. Its totient is φ = 61803419074560.
The previous prime is 155433145231291. The next prime is 155433145231319. The reversal of 155433145231300 is 3132541334551.
155433145231300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 12 ways, for example, as 50337350593924 + 105095794637376 = 7094882^2 + 10251624^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21927424 + ... + 28136776.
Almost surely, 2155433145231300 is an apocalyptic number.
155433145231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 155433145231300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169649498665108).
155433145231300 is an abundant number, since it is smaller than the sum of its proper divisors (183865852098916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
155433145231300 is a wasteful number, since it uses less digits than its factorization.
155433145231300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6210857 (or 6210850 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 40.
Adding to 155433145231300 its reverse (3132541334551), we get a palindrome (158565686565851).
The spelling of 155433145231300 in words is "one hundred fifty-five trillion, four hundred thirty-three billion, one hundred forty-five million, two hundred thirty-one thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •