Base | Representation |
---|---|
bin | 10110100111100110101… |
… | …110010110101100101011 |
3 | 12111121001121110202201102 |
4 | 112213212232112230223 |
5 | 200431304122331011 |
6 | 3150021014512015 |
7 | 220204225620242 |
oct | 26474656265453 |
9 | 5447047422642 |
10 | 1554354105131 |
11 | 54a21a409033 |
12 | 2112b206560b |
13 | b376226a5a9 |
14 | 55334369959 |
15 | 2a67410e73b |
hex | 169e6b96b2b |
1554354105131 has 2 divisors, whose sum is σ = 1554354105132. Its totient is φ = 1554354105130.
The previous prime is 1554354105113. The next prime is 1554354105193. The reversal of 1554354105131 is 1315014534551.
Together with previous prime (1554354105113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1554354105131 is a prime.
It is a super-2 number, since 2×15543541051312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1554354105431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777177052565 + 777177052566.
It is an arithmetic number, because the mean of its divisors is an integer number (777177052566).
Almost surely, 21554354105131 is an apocalyptic number.
1554354105131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1554354105131 is an equidigital number, since it uses as much as digits as its factorization.
1554354105131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 1554354105131 its reverse (1315014534551), we get a palindrome (2869368639682).
The spelling of 1554354105131 in words is "one trillion, five hundred fifty-four billion, three hundred fifty-four million, one hundred five thousand, one hundred thirty-one".
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