Base | Representation |
---|---|
bin | 10110100111101001011… |
… | …110011000100010100101 |
3 | 12111121011211022011121102 |
4 | 112213221132120202211 |
5 | 200431402431000041 |
6 | 3150025343525445 |
7 | 220205326060403 |
oct | 26475136304245 |
9 | 5447154264542 |
10 | 1554400250021 |
11 | 54a243466403 |
12 | 2113055b9885 |
13 | b376b9a6068 |
14 | 5533a53c473 |
15 | 2a6781c709b |
hex | 169e97988a5 |
1554400250021 has 2 divisors, whose sum is σ = 1554400250022. Its totient is φ = 1554400250020.
The previous prime is 1554400249999. The next prime is 1554400250033. The reversal of 1554400250021 is 1200520044551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 953573733121 + 600826516900 = 976511^2 + 775130^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1554400250021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1554400255021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777200125010 + 777200125011.
It is an arithmetic number, because the mean of its divisors is an integer number (777200125011).
Almost surely, 21554400250021 is an apocalyptic number.
It is an amenable number.
1554400250021 is a deficient number, since it is larger than the sum of its proper divisors (1).
1554400250021 is an equidigital number, since it uses as much as digits as its factorization.
1554400250021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8000, while the sum is 29.
Adding to 1554400250021 its reverse (1200520044551), we get a palindrome (2754920294572).
The spelling of 1554400250021 in words is "one trillion, five hundred fifty-four billion, four hundred million, two hundred fifty thousand, twenty-one".
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