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155441511142 = 277720755571
BaseRepresentation
bin1001000011000100001…
…0010011101011100110
3112212012222121220212021
42100301002103223212
510021321011324032
6155224151013354
714141662021141
oct2206102235346
9485188556767
10155441511142
115aa16753aa5
122616106a25a
1311872a24c38
147748341058
15409b699097
hex2431093ae6

155441511142 has 4 divisors (see below), whose sum is σ = 233162266716. Its totient is φ = 77720755570.

The previous prime is 155441511119. The next prime is 155441511143. The reversal of 155441511142 is 241115144551.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1554415111422 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 155441511098 and 155441511107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155441511143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38860377784 + ... + 38860377787.

It is an arithmetic number, because the mean of its divisors is an integer number (58290566679).

Almost surely, 2155441511142 is an apocalyptic number.

155441511142 is a deficient number, since it is larger than the sum of its proper divisors (77720755574).

155441511142 is an equidigital number, since it uses as much as digits as its factorization.

155441511142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77720755573.

The product of its digits is 16000, while the sum is 34.

Adding to 155441511142 its reverse (241115144551), we get a palindrome (396556655693).

The spelling of 155441511142 in words is "one hundred fifty-five billion, four hundred forty-one million, five hundred eleven thousand, one hundred forty-two".

Divisors: 1 2 77720755571 155441511142