Base | Representation |
---|---|
bin | 1001000100011100011… |
… | …1101111011111110111 |
3 | 112220011210211110102111 |
4 | 2101013013233133313 |
5 | 10023100340101201 |
6 | 155325024351451 |
7 | 14154111304255 |
oct | 2210707573767 |
9 | 486153743374 |
10 | 155812034551 |
11 | 60096916798 |
12 | 26245175587 |
13 | 11901715864 |
14 | 77816315d5 |
15 | 40bde88b51 |
hex | 24471ef7f7 |
155812034551 has 2 divisors, whose sum is σ = 155812034552. Its totient is φ = 155812034550.
The previous prime is 155812034503. The next prime is 155812034611. The reversal of 155812034551 is 155430218551.
It is a weak prime.
It is an emirp because it is prime and its reverse (155430218551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 155812034551 - 215 = 155812001783 is a prime.
It is a super-2 number, since 2×1558120345512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155812034051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77906017275 + 77906017276.
It is an arithmetic number, because the mean of its divisors is an integer number (77906017276).
Almost surely, 2155812034551 is an apocalyptic number.
155812034551 is a deficient number, since it is larger than the sum of its proper divisors (1).
155812034551 is an equidigital number, since it uses as much as digits as its factorization.
155812034551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120000, while the sum is 40.
The spelling of 155812034551 in words is "one hundred fifty-five billion, eight hundred twelve million, thirty-four thousand, five hundred fifty-one".
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