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156048701813401 is a prime number
BaseRepresentation
bin100011011110110011101011…
…011100000111001010011001
3202110112002222100001210201111
4203132303223130013022121
5130423200220131012101
61311515441200020321
744604101205641665
oct4336635334071231
9673462870053644
10156048701813401
11457a3978aa0981
121560334a6016a1
13690c438a16c77
142a76b2436b8a5
1513092b8cc9251
hex8deceb707299

156048701813401 has 2 divisors, whose sum is σ = 156048701813402. Its totient is φ = 156048701813400.

The previous prime is 156048701813383. The next prime is 156048701813419. The reversal of 156048701813401 is 104318107840651.

It is a balanced prime because it is at equal distance from previous prime (156048701813383) and next prime (156048701813419).

It can be written as a sum of positive squares in only one way, i.e., 151603566307600 + 4445135505801 = 12312740^2 + 2108349^2 .

It is an emirp because it is prime and its reverse (104318107840651) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 156048701813401 - 29 = 156048701812889 is a prime.

It is not a weakly prime, because it can be changed into another prime (156048701810401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78024350906700 + 78024350906701.

It is an arithmetic number, because the mean of its divisors is an integer number (78024350906701).

Almost surely, 2156048701813401 is an apocalyptic number.

It is an amenable number.

156048701813401 is a deficient number, since it is larger than the sum of its proper divisors (1).

156048701813401 is an equidigital number, since it uses as much as digits as its factorization.

156048701813401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 49.

The spelling of 156048701813401 in words is "one hundred fifty-six trillion, forty-eight billion, seven hundred one million, eight hundred thirteen thousand, four hundred one".